For an area of 8 acres, using a dose of 1 lb per 10,000 ft² and larvicide density 8.5 lbs/gal, how many gallons are required?

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Multiple Choice

For an area of 8 acres, using a dose of 1 lb per 10,000 ft² and larvicide density 8.5 lbs/gal, how many gallons are required?

Explanation:
To solve, convert the area to square feet, apply the dose, then turn pounds into gallons using the larvicide’s density. An acre has 43,560 ft^2, so 8 acres is 8 × 43,560 = 348,480 ft^2. At 1 lb per 10,000 ft^2, the required product is 348,480 / 10,000 = 34.848 lb. With a density of 8.5 lb per gallon, the gallons needed are 34.848 / 8.5 ≈ 4.10 gallons. So about 4.1 gallons are required. The other amounts would either under- or over-deliver for this area (e.g., less than 4.1 gal would not meet the dose, while more would exceed it).

To solve, convert the area to square feet, apply the dose, then turn pounds into gallons using the larvicide’s density. An acre has 43,560 ft^2, so 8 acres is 8 × 43,560 = 348,480 ft^2. At 1 lb per 10,000 ft^2, the required product is 348,480 / 10,000 = 34.848 lb. With a density of 8.5 lb per gallon, the gallons needed are 34.848 / 8.5 ≈ 4.10 gallons. So about 4.1 gallons are required. The other amounts would either under- or over-deliver for this area (e.g., less than 4.1 gal would not meet the dose, while more would exceed it).

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